What is the domain of 1/(x^2+1+2x) ?

The domain of 1/(x^2+1+2x) is x -1

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domain of 1/(x^2+1+2x)

domain

\frac{1}{x ^{2} + 1 + 2 x}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

f (x) = - 3 - x - 2

f (x) = \frac{( x - 4 )}{3 x - x ^{2}}

f (x) = x^{2} - x^{4}

x - 2 y = 2

y = - x^{2} + 2 x - 3

What is the domain of 1/(x^2+1+2x) ?
The domain of 1/(x^2+1+2x) is x<-1\lor x>-1