What is the critical-sin(x)-9 ?

The critical-sin(x)-9 is x= pi/2+2pin,x=(3pi)/2+2pin

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critical-sin(x)-9

critical points

- sin (x) - 9

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Solution steps

- sin (x) - 9

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Identify critical points not in

f (x)

domain

Domain of

- sin (x) - 9 : - \infty < x < \infty

All critical points are in domain

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

\frac{4}{x - 3}

5 x + 2 y = 6

3 x^{2} - 4

3 - 2 x^{3}

f (x) = \frac{x ^{2}}{x ^{2} + x - 90}

What is the critical-sin(x)-9 ?
The critical-sin(x)-9 is x= pi/2+2pin,x=(3pi)/2+2pin