What is the critical f(x)= x/(x^2+9x+18) ?

The critical f(x)= x/(x^2+9x+18) is x=-3sqrt(2),x=3sqrt(2)

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critical f(x)= x/(x^2+9x+18)

critical points

f (x) = \frac{x}{x ^{2} + 9 x + 18}

x = - 32, x = 32

Solution steps

\frac{x}{x ^{2} + 9 x + 18}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 32, x = 32, x = - 6, x = - 3

Identify critical points not in

f (x)

domain

Domain of

\frac{x}{x ^{2} + 9 x + 18} : x < - 6 or - 6 < x < - 3 or x > - 3

\frac{x}{x ^{2} + 9 x + 18}

is not defined at

x = - 6, x = - 3

, therefore:

x = - 32, x = 32

f (x) = \frac{2 x + 10}{x ^{2} + 5 x}

3 x + 4 y = 24

f (x) = 8 x^{2} - 2 x - 15

m = 7, (- 2, - 9)

What is the critical f(x)= x/(x^2+9x+18) ?
The critical f(x)= x/(x^2+9x+18) is x=-3sqrt(2),x=3sqrt(2)