What is the domain of f(x)=(4*[5*(x^2)-1]-8)^{(1/2)} ?

The domain of f(x)=(4*[5*(x^2)-1]-8)^{(1/2)} is x = (3/5)^{1/2}

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domain of f(x)=(4[5(x^2)-1]-8)^{(1/2)}

domain

f (x) = (4 \cdot [5 \cdot (x^{2}) - 1] - 8)^{(\frac{1}{2})}

x \leq - (\frac{3}{5})^{\frac{1}{2}} or x \geq (\frac{3}{5})^{\frac{1}{2}}

Interval Notation

(- \infty, - (\frac{3}{5})^{\frac{1}{2}}] \cup [(\frac{3}{5})^{\frac{1}{2}}, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - (\frac{3}{5})^{\frac{1}{2}} or x \geq (\frac{3}{5})^{\frac{1}{2}}

The function domain

x \leq - (\frac{3}{5})^{\frac{1}{2}} or x \geq (\frac{3}{5})^{\frac{1}{2}}

x^{9} - 9 x

f (x) = \frac{( x - 2 ) ^{3}}{64} + 3

f (x) = - \frac{10 x}{x ^{2} + 25}

y = cos (2 x)

1.5 cos (6 x - 3.2)

What is the domain of f(x)=(4*[5*(x^2)-1]-8)^{(1/2)} ?
The domain of f(x)=(4*[5*(x^2)-1]-8)^{(1/2)} is x<=-(3/5)^{1/2}\lor x>= (3/5)^{1/2}