What is the domain of (sqrt(3x))/(x+9) ?

The domain of (sqrt(3x))/(x+9) is x>= 0

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domain of (sqrt(3x))/(x+9)

domain

\frac{3 x}{x + 9}

x \geq 0

Interval Notation

[0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = - 9

Combine real regions and undefined points for final function domain

x \geq 0

f (x) = 3

\frac{x ^{2} + 8 x + 15}{x + 5}

f (x) = - e^{- x}

f (x) = 3 sin (8 π x + \frac{3}{2})

f (x) = x^{2} + 6 x + 8

What is the domain of (sqrt(3x))/(x+9) ?
The domain of (sqrt(3x))/(x+9) is x>= 0