What is the domain of sqrt(x^2-5) ?

The domain of sqrt(x^2-5) is x = sqrt(5)

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domain of sqrt(x^2-5)

domain

x^{2} - 5

x \leq - 5 or x \geq 5

Interval Notation

(- \infty, - 5] \cup [5, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 5 or x \geq 5

The function domain

x \leq - 5 or x \geq 5

f (x) = \frac{1 - x}{3 x + 1}

f (x) = - 2 x^{2} + 7 x - 5

f (x) = \frac{2}{\frac{2}{x}}

(- 2, 1), (5, 0)

y = - 2 x, (- 3, 6)

What is the domain of sqrt(x^2-5) ?
The domain of sqrt(x^2-5) is x<=-sqrt(5)\lor x>= sqrt(5)