What is the critical f(x)= 1/(x^2+10x+28) ?

The critical f(x)= 1/(x^2+10x+28) is x=-5

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critical f(x)= 1/(x^2+10x+28)

critical points

f (x) = \frac{1}{x ^{2} + 10 x + 28}

x = - 5

Solution steps

\frac{1}{x ^{2} + 10 x + 28}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 5

Identify critical points not in

f (x)

domain

Domain of

\frac{1}{x ^{2} + 10 x + 28} : - \infty < x < \infty

All critical points are in domain

x = - 5

f (x) = \frac{- x ^{2} - 2 x + 4}{x + 3}

8 x + 3

- x + 2

f (x) = 3 - 4 x - x^{2}

3 x - 12

What is the critical f(x)= 1/(x^2+10x+28) ?
The critical f(x)= 1/(x^2+10x+28) is x=-5