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Popular >

extreme f(x)= 2/(x^2+1)

Solution

extreme points

f (x) = \frac{2}{x ^{2} + 1}

Solution

Maximum (0, 2)

Solution steps

f^{'} (x) = - \frac{4 x}{( x ^{2} + 1 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < \infty

Plug

x = 0

into

\frac{2}{x ^{2} + 1} : 2

Maximum (0, 2)

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\frac{3 x}{x - 2}

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f (x) = y^{2} + 8

slope of 4x-3y=-24 slope

4 x - 3 y = - 24

Frequently Asked Questions (FAQ)

What is the extreme f(x)= 2/(x^2+1) ?
The extreme f(x)= 2/(x^2+1) is Maximum(0,2)