What is the domain of (sqrt(x^2-25))/(\frac{x^2){x^2-1}} ?

The domain of (sqrt(x^2-25))/(\frac{x^2){x^2-1}} is x = 5

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domain of (sqrt(x^2-25))/(\frac{x^2){x^2-1}}

domain

\frac{x ^{2} - 25}{\frac{x ^{2}}{x ^{2} - 1}}

x \leq - 5 or x \geq 5

Interval Notation

(- \infty, - 5] \cup [5, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 5 or x \geq 5

Find undefined (singularity) points:

x = 0, x = 1, x = - 1

Combine real regions and undefined points for final function domain

x \leq - 5 or x \geq 5

\frac{2 x}{x ^{2} - 1}

y = x^{2} - 2 x

f (x) = \frac{3 x + 1}{x ^{2}}

(- 1, - 4), (- 10, 5)

2 + 3 + 6 x

What is the domain of (sqrt(x^2-25))/(\frac{x^2){x^2-1}} ?
The domain of (sqrt(x^2-25))/(\frac{x^2){x^2-1}} is x<=-5\lor x>= 5