What is the domain of f(x)=sqrt(2(1/x)-1) ?

The domain of f(x)=sqrt(2(1/x)-1) is 0<x<= 2

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domain of f(x)=sqrt(2(1/x)-1)

domain

f (x) = 2 (\frac{1}{x}) - 1

0 < x \leq 2

Interval Notation

(0, 2]

Solution steps

Find non-negative values for radicals:

0 < x \leq 2

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

0 < x \leq 2

f (x) = x + 2 + 5

(9, - 10), (- 3, 4)

f (x) = 3 x + 2

f (x) = \frac{10 x ^{3}}{5 x ^{2} + 1}

5 - x^{3}

What is the domain of f(x)=sqrt(2(1/x)-1) ?
The domain of f(x)=sqrt(2(1/x)-1) is 0<x<= 2