What is the asymptotes of y=(2x^2+x+3)/(3x^2+2x-1) ?

The asymptotes of y=(2x^2+x+3)/(3x^2+2x-1) is Vertical: x=-1,x= 1/3 ,Horizontal: y= 2/3

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asymptotes of y=(2x^2+x+3)/(3x^2+2x-1)

asymptotes

y = \frac{2 x ^{2} + x + 3}{3 x ^{2} + 2 x - 1}

Vertical : x = - 1, x = \frac{1}{3}, Horizontal : y = \frac{2}{3}

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} + x + 3}{3 x ^{2} + 2 x - 1} : x = - 1, x = \frac{1}{3}

Horizontal Asymptotes of

\frac{2 x ^{2} + x + 3}{3 x ^{2} + 2 x - 1} : y = \frac{2}{3}

Slant Asymptotes of

\frac{2 x ^{2} + x + 3}{3 x ^{2} + 2 x - 1} :

None

Vertical : x = - 1, x = \frac{1}{3}, Horizontal : y = \frac{2}{3}

y = ln (x + 1)

2 ln (3 - x) - 4

f (x) = 2 x^{2} - 3, x \geq 0

y - 4 = 0

\frac{4 + 8 x + 4 x ^{2}}{x ^{2} - 2 x + 1}

What is the asymptotes of y=(2x^2+x+3)/(3x^2+2x-1) ?
The asymptotes of y=(2x^2+x+3)/(3x^2+2x-1) is Vertical: x=-1,x= 1/3 ,Horizontal: y= 2/3