What is the domain of f(x)=(4x)/(sqrt(x+9)) ?

The domain of f(x)=(4x)/(sqrt(x+9)) is x>-9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(4x)/(sqrt(x+9))

domain

f (x) = \frac{4 x}{x + 9}

x > - 9

Interval Notation

(- 9, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 9

Find undefined (singularity) points:

x = - 9

Combine real regions and undefined points for final function domain

x > - 9

\frac{4 x ^{2}}{x ^{2} - 4 x + 4}

\frac{4 x + 3}{x ( x + 3 )}

x - 5 + 3

x^{3} + 6

f (x) = ln (x^{2} + 1)

What is the domain of f(x)=(4x)/(sqrt(x+9)) ?
The domain of f(x)=(4x)/(sqrt(x+9)) is x>-9