What is the extreme f(x)=2cos(x) ?

The extreme f(x)=2cos(x) is Maximum(2pin,2),Minimum(pi+2pin,-2)

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extreme f(x)=2cos(x)

extreme points

f (x) = 2 cos (x)

Maximum (2 πn, 2), Minimum (π + 2 πn, - 2)

Solution steps

Find the critical points:

x = 2 πn, x = π + 2 πn

Domain of

2 cos (x) : - \infty < x < \infty

Find intervals:

Decreasing

: 2 πn < x < π + 2 πn,

Increasing

: π + 2 πn < x < 2 π + 2 πn

Plug the extreme point

x = 2 πn

into

2 cos (x) \Rightarrow y = 2

Maximum (2 πn, 2)

Plug the extreme point

x = π + 2 πn

into

2 cos (x) \Rightarrow y = - 2

Minimum (π + 2 πn, - 2)

Maximum (2 πn, 2), Minimum (π + 2 πn, - 2)

g (x) = 7 - x

f (x) = 2 x - 3

(3 z + 2)

f (x) = - \frac{3}{x - 4}

f (x) = \frac{x ^{2}}{3 - x}

What is the extreme f(x)=2cos(x) ?
The extreme f(x)=2cos(x) is Maximum(2pin,2),Minimum(pi+2pin,-2)