What is the inverse of f(x)=\sqrt[3]{x}+7 ?

The inverse of f(x)=\sqrt[3]{x}+7 is x^3-21x^2+147x-343

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inverse of f(x)=\sqrt[3]{x}+7

inverse

f (x) = 3 x + 7

x^{3} - 21 x^{2} + 147 x - 343

Solution steps

y = 3 x + 7

Replace

x

with

y

x = 3 y + 7

Solve for

y, x = 3 y + 7

x^{3} - 21 x^{2} + 147 x - 343

f (x) = \frac{3 x ^{2} - 4 x + 5}{x - 3}

f (x) = 18 - x

f (x) = \frac{x ^{2} + 9}{3 x ^{2} - 14 x - 5}

(2, 5), (9, 8)

f (x) = x + 1

What is the inverse of f(x)=\sqrt[3]{x}+7 ?
The inverse of f(x)=\sqrt[3]{x}+7 is x^3-21x^2+147x-343