What is the domain of f(x)=sqrt(3-x)+4 ?

The domain of f(x)=sqrt(3-x)+4 is x<= 3

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domain of f(x)=sqrt(3-x)+4

domain

f (x) = 3 - x + 4

x \leq 3

Interval Notation

(- \infty, 3]

Solution steps

Find non-negative values for radicals:

x \leq 3

The function domain

x \leq 3

f (x) = \frac{8 - x}{2}

f (x) = 6 - x

(8.5) (5.3)

f (x) = 3 x

\frac{x ^{2} - 9}{x - 5}

What is the domain of f(x)=sqrt(3-x)+4 ?
The domain of f(x)=sqrt(3-x)+4 is x<= 3