What is the domain of f(x)= 1/(sqrt(3+x)) ?

The domain of f(x)= 1/(sqrt(3+x)) is x>-3

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domain of f(x)= 1/(sqrt(3+x))

domain

f (x) = \frac{1}{3 + x}

x > - 3

Interval Notation

(- 3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 3

Find undefined (singularity) points:

x = - 3

Combine real regions and undefined points for final function domain

x > - 3

y = x^{2} - 4

y^{3}

y = x^{2} + 4

f (x) = 1 - x

f (x) = \frac{3 x + 2}{x - 1}

What is the domain of f(x)= 1/(sqrt(3+x)) ?
The domain of f(x)= 1/(sqrt(3+x)) is x>-3