What is the domain of (sqrt(25-x^2))/(sqrt(x+1)) ?

The domain of (sqrt(25-x^2))/(sqrt(x+1)) is -1<x<= 5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of (sqrt(25-x^2))/(sqrt(x+1))

domain

\frac{25 - x ^{2}}{x + 1}

- 1 < x \leq 5

Interval Notation

(- 1, 5]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 5

Find undefined (singularity) points:

x = - 1

Combine real regions and undefined points for final function domain

- 1 < x \leq 5

f (x) = \frac{2}{x - 4}

5 x - y = 2

\frac{8 x}{x ^{2} + 1}

f (x) = 4 x^{2} + 9

\frac{1}{x + 5}

What is the domain of (sqrt(25-x^2))/(sqrt(x+1)) ?
The domain of (sqrt(25-x^2))/(sqrt(x+1)) is -1<x<= 5