What is the perpendicular \at (-7-5),y=5 ?

The perpendicular \at (-7-5),y=5 is x=b

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perpendicular \at (-7-5),y=5

perpendicular

at (- 7 - 5), y = 5

x = b

Solution steps

Find the slope of

(- 7 - 5) : m = 0

Compute the slope of the perpendicular line:

m_{p} = \infty

Line with slope m=

\infty : x = b

x = b

f (x) = cos (3 x)

\frac{2 x ^{2} - 5 x - 25}{2 x ^{2} - 5 x + 2}

f (x) = \frac{x ^{2} - 2 x + 5}{3 x - 2}

f (x) = \frac{1 - 6 t}{5 + t}

(2, 8), (12, 2)

What is the perpendicular \at (-7-5),y=5 ?
The perpendicular \at (-7-5),y=5 is x=b