What is the critical f(x)=4xsqrt(2x^2+2) ?

The critical f(x)=4xsqrt(2x^2+2) is None

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critical f(x)=4xsqrt(2x^2+2)

critical points

f (x) = 4 x 2 x^{2} + 2

None

Solution steps

4 x 2 x^{2} + 2

Find where

f^{'} (x)

is equal to zero or undefined

None

cos (5 x)

f (x) = \frac{x ^{2} - 4}{2 x ^{2}}

\frac{1}{4} x + 3

y - 3 = 5 (x - 2)

f (x) = 2 x^{3} - 9

What is the critical f(x)=4xsqrt(2x^2+2) ?
The critical f(x)=4xsqrt(2x^2+2) is None