What is the domain of f(x)= 1/(9-x^2) ?

The domain of f(x)= 1/(9-x^2) is x 3

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domain of f(x)= 1/(9-x^2)

domain

f (x) = \frac{1}{9 - x ^{2}}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

sin (5 x)

f (x) = x^{2} + 9

7 x - 2 y = 14

\frac{1}{\frac{1}{x}}

2 (x - 1)^{2} + 3

What is the domain of f(x)= 1/(9-x^2) ?
The domain of f(x)= 1/(9-x^2) is x<-3\lor-3<x<3\lor x>3