What is the perpendicular y= 2/5 x+2,(0,2) ?

The perpendicular y= 2/5 x+2,(0,2) is y=-5/2 x+2

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perpendicular y= 2/5 x+2,(0,2)

perpendicular

y = \frac{2}{5} x + 2, (0, 2)

y = - \frac{5}{2} x + 2

Solution steps

Find the line

y = mx + b

perpendicular to

y = \frac{2}{5} x + 2

that passes through

(0, 2)

Find the slope of

y = \frac{2}{5} x + 2 : m = \frac{2}{5}

Compute the slope of the perpendicular line:

m_{p} = - \frac{5}{2}

Find the line with slope m=

- \frac{5}{2}

and passing through

(0, 2) : y = - \frac{5}{2} x + 2

y = - \frac{5}{2} x + 2

f (x) = x - 4

\frac{49 - x ^{2}}{x ^{2} - 16}

\frac{3 + 4 x}{1 - 5 x}

f (x) = \frac{2 x}{x + 1}

e^{x}

What is the perpendicular y= 2/5 x+2,(0,2) ?
The perpendicular y= 2/5 x+2,(0,2) is y=-5/2 x+2