What is the domain of f(x)=(x/(x+1))/(x/(x+1)+1) ?

The domain of f(x)=(x/(x+1))/(x/(x+1)+1) is x -1/2

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domain of f(x)=(x/(x+1))/(x/(x+1)+1)

domain

f (x) = \frac{\frac{x}{x + 1}}{\frac{x}{x + 1} + 1}

x < - 1 or - 1 < x < - \frac{1}{2} or x > - \frac{1}{2}

Interval Notation

(- \infty, - 1) \cup (- 1, - \frac{1}{2}) \cup (- \frac{1}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{1}{2}, x = - 1

The function domain

x < - 1 or - 1 < x < - \frac{1}{2} or x > - \frac{1}{2}

(5.2) (5.8)

f (x) = \frac{x + 3}{2 x ^{2} - 1}

ln (x - 8)

f (x) = 2 x^{3} + x

f (x) = x^{4} - 12 x^{3} + 30 x^{2} + 36 x

What is the domain of f(x)=(x/(x+1))/(x/(x+1)+1) ?
The domain of f(x)=(x/(x+1))/(x/(x+1)+1) is x<-1\lor-1<x<-1/2 \lor x>-1/2