en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

distance (5,8),(-3,4)

Solution

distance

(5, 8), (- 3, 4)

Solution

45

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(5, 8)

and

(- 3, 4)

is

= (- 3 - 5)^{2} + (4 - 8)^{2}

Simplify

= 45

Popular Examples

midpoint (5,-6),(-7,-2)midpoint

(5, - 6), (- 7, - 2)

domain of f(x)=((x^4))/(x^2+x-12)domain

f (x) = \frac{( x ^{4} )}{x ^{2} + x - 12}

shift f(x)=5sin(2/3 x+2/9 pi)shift

f (x) = 5 sin (\frac{2}{3} x + \frac{2}{9} π)

asymptotes of f(x)=(x^2+x-6)/(x-3)asymptotes

f (x) = \frac{x ^{2} + x - 6}{x - 3}

extreme f(x)=x^4e^x-4 extreme points

f (x) = x^{4} e^{x} - 4

Frequently Asked Questions (FAQ)

What is the distance (5,8),(-3,4) ?
The distance (5,8),(-3,4) is 4sqrt(5)