What is the extreme f(x)=x^4e^x-4 ?

The extreme f(x)=x^4e^x-4 is Maximum(-4,(256)/(e^4)-4),Minimum(0,-4)

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extreme f(x)=x^4e^x-4

extreme points

f (x) = x^{4} e^{x} - 4

Maximum (- 4, \frac{256}{e ^{4}} - 4), Minimum (0, - 4)

Solution steps

f^{'} (x) = e^{x} x^{4} + 4 e^{x} x^{3}

Find intervals:

Increasing

: - \infty < x < - 4,

Decreasing

: - 4 < x < 0,

Increasing

: 0 < x < \infty

Plug

x = - 4

into

x^{4} e^{x} - 4 : \frac{256}{e ^{4}} - 4

Maximum (- 4, \frac{256}{e ^{4}} - 4)

Plug

x = 0

into

x^{4} e^{x} - 4 : - 4

Minimum (0, - 4)

Maximum (- 4, \frac{256}{e ^{4}} - 4), Minimum (0, - 4)

25 - x^{2}

\frac{ln ( x - 3 )}{ln ( e ^{x} - e ^{3} )}

cos (6 x)

g (x) = \frac{x}{x + 7}

\frac{1 + x ^{4}}{x ^{2} - x ^{4}}

What is the extreme f(x)=x^4e^x-4 ?
The extreme f(x)=x^4e^x-4 is Maximum(-4,(256)/(e^4)-4),Minimum(0,-4)