What is the domain of sqrt(x^2+8x+14) ?

The domain of sqrt(x^2+8x+14) is x = sqrt(2)-4

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domain of sqrt(x^2+8x+14)

domain

x^{2} + 8 x + 14

x \leq - 2 - 4 or x \geq 2 - 4

Interval Notation

(- \infty, - 2 - 4] \cup [2 - 4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 - 4 or x \geq 2 - 4

The function domain

x \leq - 2 - 4 or x \geq 2 - 4

f (x) = \frac{y - 10}{y ^{2} + 3}

12 x + 3 y = - 18

\frac{x + 2}{x ^{3} + 8}

f (x) = \frac{2 x - 4}{3}

\frac{x ^{2} - 25}{x - 5}

What is the domain of sqrt(x^2+8x+14) ?
The domain of sqrt(x^2+8x+14) is x<=-sqrt(2)-4\lor x>= sqrt(2)-4