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Popular >

distance (1,1),(7,5)

Solution

distance

(1, 1), (7, 5)

Solution

213

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(1, 1)

and

(7, 5)

is

= (7 - 1)^{2} + (5 - 1)^{2}

Simplify

= 213

Popular Examples

critical f(x)=(10)/(x^2+5)critical points

f (x) = \frac{10}{x ^{2} + 5}

domain of x/(sqrt(x)-9)domain

\frac{x}{x - 9}

domain of f(x)=(x-8)/(x+7)domain

f (x) = \frac{x - 8}{x + 7}

distance (3,7),(6,5)distance

(3, 7), (6, 5)

inverse of f(x)=-(x-5)^2+2 inverse

f (x) = - (x - 5)^{2} + 2

Frequently Asked Questions (FAQ)

What is the distance (1,1),(7,5) ?
The distance (1,1),(7,5) is 2sqrt(13)