What is the domain of f(x)=ln(x/(1-x^2)) ?

The domain of f(x)=ln(x/(1-x^2)) is x<-1\lor 0<x<1

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domain of f(x)=ln(x/(1-x^2))

domain

f (x) = ln (\frac{x}{1 - x ^{2}})

x < - 1 or 0 < x < 1

Interval Notation

(- \infty, - 1) \cup (0, 1)

Solution steps

Find positive values for logs:

x < - 1 or 0 < x < 1

Find undefined (singularity) points:

x = 1, x = - 1

Combine real regions and undefined points for final function domain

x < - 1 or 0 < x < 1

y = - 6

f (x) = - 3 x + 1

3 x

\frac{1 - x}{1 + x}

f (x) = \frac{55 x}{15 - x}

What is the domain of f(x)=ln(x/(1-x^2)) ?
The domain of f(x)=ln(x/(1-x^2)) is x<-1\lor 0<x<1