What is the domain of f(x)=sqrt(16-x^4) ?

The domain of f(x)=sqrt(16-x^4) is -2<= x<= 2

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domain of f(x)=sqrt(16-x^4)

domain

f (x) = 16 - x^{4}

- 2 \leq x \leq 2

Interval Notation

[- 2, 2]

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 2

The function domain

- 2 \leq x \leq 2

f (x) = \frac{3}{2 x - 1}

f (x) = ln (5 x)

y = 5 x + 4

f (x) = x^{2} + 5 x + 2

f (x) = ln (x - 4) + 2

What is the domain of f(x)=sqrt(16-x^4) ?
The domain of f(x)=sqrt(16-x^4) is -2<= x<= 2