What is the domain of f(x)=sqrt(x^2-5x+6) ?

The domain of f(x)=sqrt(x^2-5x+6) is x = 3

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domain of f(x)=sqrt(x^2-5x+6)

domain

f (x) = x^{2} - 5 x + 6

x \leq 2 or x \geq 3

Solution steps

Find non-negative values for radicals:

x \leq 2 or x \geq 3

The function domain

x \leq 2 or x \geq 3

\frac{- 8 x + 75}{9 x - 61}

f (x) = \frac{3 x ^{2} + 6 x + 3}{x ^{2} + x}

f (x) = 1 + x^{2}

x + 3

f (x) = e^{x + 3}

What is the domain of f(x)=sqrt(x^2-5x+6) ?
The domain of f(x)=sqrt(x^2-5x+6) is x<= 2\lor x>= 3