What is the domain of f(x)=(sqrt(x-1))/(x-2) ?

The domain of f(x)=(sqrt(x-1))/(x-2) is 1 2

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domain of f(x)=(sqrt(x-1))/(x-2)

domain

f (x) = \frac{x - 1}{x - 2}

1 \leq x < 2 or x > 2

Interval Notation

[1, 2) \cup (2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

1 \leq x < 2 or x > 2

f (x) = 2 x + 3 - 1

y = 1 x + 0, (- 4, - 6)

(- 2, 4), (3, - 6)

\frac{x + 6}{x ^{2} - 36}

y = \frac{1}{3} x + 4

What is the domain of f(x)=(sqrt(x-1))/(x-2) ?
The domain of f(x)=(sqrt(x-1))/(x-2) is 1<= x<2\lor x>2