What is the shift y=0.9(sin(pi/3-x)+0.01) ?

The shift y=0.9(sin(pi/3-x)+0.01) is Phase: pi/3 , Vertical:0.009

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shift y=0.9(sin(pi/3-x)+0.01)

shift

y = 0.9 (sin (\frac{π}{3} - x) + 0.01)

Phase : \frac{π}{3}, Vertical : 0.009

Solution steps

f (x) = 0.9 (sin (\frac{π}{3} - x) + 0.01)

g (B x - C) = sin (\frac{π}{3} - x), B = - 1, C = - \frac{π}{3}, D = 0.009

Therefore, the phase shift

\frac{C}{B}

\frac{- \frac{π}{3}}{- 1}

\frac{π}{3}

The vertical shift

D

0.009

0.009

f (x) = 1 - x^{3}

f (x) = x e

f (x) = \frac{x + 6}{x - 3}

300 sin (7 t + π)

x^{3} - 7

What is the shift y=0.9(sin(pi/3-x)+0.01) ?
The shift y=0.9(sin(pi/3-x)+0.01) is Phase: pi/3 , Vertical:0.009