What is the asymptotes of f(x)= 1/(x^2-4)-3 ?

The asymptotes of f(x)= 1/(x^2-4)-3 is Vertical: x=-2,x=2,Horizontal: y=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)= 1/(x^2-4)-3

asymptotes

f (x) = \frac{1}{x ^{2} - 4} - 3

Vertical : x = - 2, x = 2, Horizontal : y = - 3

Solution steps

Vertical asymptotes of

\frac{1}{x ^{2} - 4} - 3 : x = - 2, x = 2

Horizontal Asymptotes of

\frac{1}{x ^{2} - 4} - 3 : y = - 3

Slant Asymptotes of

\frac{1}{x ^{2} - 4} - 3 :

None

Vertical : x = - 2, x = 2, Horizontal : y = - 3

f (x) = \frac{8}{3 x + 9}

f (x) = \frac{x + 1}{x ^{2} - 4}

f (x) = \frac{- x ^{2}}{x ^{2} - 2 x + 8}

f (x) = - \frac{1}{3} x - \frac{1}{3}

9

What is the asymptotes of f(x)= 1/(x^2-4)-3 ?
The asymptotes of f(x)= 1/(x^2-4)-3 is Vertical: x=-2,x=2,Horizontal: y=-3