What is the extreme f(x)=x^3-2x^2-4x+2 ?

The extreme f(x)=x^3-2x^2-4x+2 is Maximum(-2/3 , 94/27),Minimum(2,-6)

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extreme f(x)=x^3-2x^2-4x+2

extreme points

f (x) = x^{3} - 2 x^{2} - 4 x + 2

Maximum (- \frac{2}{3}, \frac{94}{27}), Minimum (2, - 6)

Solution steps

f^{'} (x) = 3 x^{2} - 4 x - 4

Find intervals:

Increasing

: - \infty < x < - \frac{2}{3},

Decreasing

: - \frac{2}{3} < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - \frac{2}{3}

into

x^{3} - 2 x^{2} - 4 x + 2 : \frac{94}{27}

Maximum (- \frac{2}{3}, \frac{94}{27})

Plug

x = 2

into

x^{3} - 2 x^{2} - 4 x + 2 : - 6

Minimum (2, - 6)

Maximum (- \frac{2}{3}, \frac{94}{27}), Minimum (2, - 6)

f (x) = 5^{x - 2}

f (x) = 2 x^{3} - 3 x^{2} - 12 x

\frac{8 x - 10}{- 8 x - 1}

4 x + 2 y = 5

f (x) = \frac{2 x ^{3} + 5 x + 3}{3 x ^{3} + 2 x - 4}

What is the extreme f(x)=x^3-2x^2-4x+2 ?
The extreme f(x)=x^3-2x^2-4x+2 is Maximum(-2/3 , 94/27),Minimum(2,-6)