What is the critical f(x)=sqrt(49-x^2) ?

The critical f(x)=sqrt(49-x^2) is x=-7,x=0,x=7

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critical f(x)=sqrt(49-x^2)

critical points

f (x) = 49 - x^{2}

x = - 7, x = 0, x = 7

Solution steps

49 - x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = - 7, x = 7

Identify critical points not in

f (x)

domain

Domain of

49 - x^{2} : - 7 \leq x \leq 7

All critical points are in domain

x = - 7, x = 0, x = 7

I + 1

f (x) = 4 - x^{2}

3 x - y = 5

f (x) = x - 16

What is the critical f(x)=sqrt(49-x^2) ?
The critical f(x)=sqrt(49-x^2) is x=-7,x=0,x=7