What is the asymptotes of f(x)=(14)/((x-5)(x+1)) ?

The asymptotes of f(x)=(14)/((x-5)(x+1)) is Vertical: x=-1,x=5,Horizontal: y=0

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asymptotes of f(x)=(14)/((x-5)(x+1))

asymptotes

f (x) = \frac{14}{( x - 5 ) ( x + 1 )}

Vertical : x = - 1, x = 5, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{14}{( x - 5 ) ( x + 1 )} : x = - 1, x = 5

Horizontal Asymptotes of

\frac{14}{( x - 5 ) ( x + 1 )} : y = 0

Slant Asymptotes of

\frac{14}{( x - 5 ) ( x + 1 )} :

None

Vertical : x = - 1, x = 5, Horizontal : y = 0

x^{4} - 4 x^{3} + 9

f (x) = (\frac{1}{12})^{x}

f (x) = lo g_{6} (x^{5})

f (x) = \frac{1}{4} x^{3}

2 + x - 1

What is the asymptotes of f(x)=(14)/((x-5)(x+1)) ?
The asymptotes of f(x)=(14)/((x-5)(x+1)) is Vertical: x=-1,x=5,Horizontal: y=0