What is the range of sqrt(-x^2-6x+12) ?

The range of sqrt(-x^2-6x+12) is 0<= f(x)<= sqrt(21)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of sqrt(-x^2-6x+12)

range

- x^{2} - 6 x + 12

0 \leq f (x) \leq 21

Interval Notation

[0, 21]

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

- x^{2} - 6 x + 12 : - 21 - 3 \leq x \leq 21 - 3

Extreme Points of

- x^{2} - 6 x + 12 :

Minimum

(- 3 - 21, 0),

Maximum

(- 3, 21),

Minimum

(21 - 3, 0)

Find the range for the interval

- 21 - 3 \leq x \leq 21 - 3 : 0 \leq f (x) \leq 21

Combine the ranges of all domain intervals to obtain the function range

0 \leq f (x) \leq 21

- x^{2} + 2 x + 4

\frac{x ^{3} - x ^{2} - 2 x}{x - 2}

g (x) = x + 8

(\frac{1}{2})^{x - 3}

f (x) = \frac{- 2 x ^{2}}{x ^{2} - 3}

What is the range of sqrt(-x^2-6x+12) ?
The range of sqrt(-x^2-6x+12) is 0<= f(x)<= sqrt(21)