What is the asymptotes of y= 6/(3+2x) ?

The asymptotes of y= 6/(3+2x) is Vertical: x=-3/2 ,Horizontal: y=0

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asymptotes of y= 6/(3+2x)

asymptotes

y = \frac{6}{3 + 2 x}

Vertical : x = - \frac{3}{2}, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{6}{3 + 2 x} : x = - \frac{3}{2}

Horizontal Asymptotes of

\frac{6}{3 + 2 x} : y = 0

Slant Asymptotes of

\frac{6}{3 + 2 x} :

None

Vertical : x = - \frac{3}{2}, Horizontal : y = 0

g (x) = x^{2} - 6 x - 27

f (x) = 15.5 - 5 t

f (x) = x^{3} - 9 x^{2} - x + 9

- 4 x^{4} + 5 x^{3} - x^{2}

5 x^{3} - 5 x^{2} - 4

What is the asymptotes of y= 6/(3+2x) ?
The asymptotes of y= 6/(3+2x) is Vertical: x=-3/2 ,Horizontal: y=0