What is the domain of ((x^2+2x-1))/((x^2-1)^2) ?

The domain of ((x^2+2x-1))/((x^2-1)^2) is x 1

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domain of ((x^2+2x-1))/((x^2-1)^2)

domain

\frac{( x ^{2} + 2 x - 1 )}{( x ^{2} - 1 ) ^{2}}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

f (x) = x^{2} - 3 x - 5

f (x) = \frac{x + 2}{x - 10}

f (x) = 6 cos (3 x - \frac{π}{4})

f (x) = x + 7 + 2

f (x) = x^{3} - 6 x

What is the domain of ((x^2+2x-1))/((x^2-1)^2) ?
The domain of ((x^2+2x-1))/((x^2-1)^2) is x<-1\lor-1<x<1\lor x>1