What is the inverse of f(x)=log_{1/2}(-4x) ?

The inverse of f(x)=log_{1/2}(-4x) is -1/(2^{x+2)}

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inverse of f(x)=log_{1/2}(-4x)

inverse

f (x) = lo g_{\frac{1}{2}} (- 4 x)

- \frac{1}{2 ^{x + 2}}

Solution steps

y = lo g_{\frac{1}{2}} (- 4 x)

Replace

x

with

y

x = lo g_{\frac{1}{2}} (- 4 y)

Solve for

y, x = lo g_{\frac{1}{2}} (- 4 y)

- \frac{1}{2 ^{x + 2}}

y = tan (\frac{π}{7} x)

f (x) = - lo g_{2} (x)

f (x) = 2 x^{2} + 4 x - 6

f (x) = - 2 x^{2} - 2 x + 10

What is the inverse of f(x)=log_{1/2}(-4x) ?
The inverse of f(x)=log_{1/2}(-4x) is -1/(2^{x+2)}