What is the domain of sqrt(4-x)-sqrt(x^2-9) ?

The domain of sqrt(4-x)-sqrt(x^2-9) is x<=-3\lor 3<= x<= 4

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domain of sqrt(4-x)-sqrt(x^2-9)

domain

4 - x - x^{2} - 9

x \leq - 3 or 3 \leq x \leq 4

Interval Notation

(- \infty, - 3] \cup [3, 4]

Solution steps

Find non-negative values for radicals:

x \leq - 3 or 3 \leq x \leq 4

The function domain

x \leq - 3 or 3 \leq x \leq 4

f (x) = lo g_{2 x + 3} (x^{2} + 3 x - 4)

y = \frac{( x + 3 ) ( x - 4 )}{( 3 x + 1 ) ( 2 x - 3 )}

f (x) = \frac{x ^{3} + 8}{x ^{2} + 5 x + 6}

f (x) = sin^{3} (x)

f (x) = ln (x + 1)

What is the domain of sqrt(4-x)-sqrt(x^2-9) ?
The domain of sqrt(4-x)-sqrt(x^2-9) is x<=-3\lor 3<= x<= 4