What is the domain of (40)/((t+5)^2) ?

The domain of (40)/((t+5)^2) is t -5

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domain of (40)/((t+5)^2)

domain

\frac{40}{( t + 5 ) ^{2}}

t < - 5 or t > - 5

Interval Notation

(- \infty, - 5) \cup (- 5, \infty)

Solution steps

Find undefined (singularity) points:

t = - 5

The function domain

t < - 5 or t > - 5

f (x) = x^{3} + 1

- 9 - x^{2}

(3.2) (- 11.3)

f (x) = \frac{x - 2}{x ^{2} + 1}

f (x) = 2 + \frac{x ^{3}}{x + 5}

What is the domain of (40)/((t+5)^2) ?
The domain of (40)/((t+5)^2) is t<-5\lor t>-5