en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)= 1/(1+x^2)

Solution

extreme points

f (x) = \frac{1}{1 + x ^{2}}

Solution

Maximum (0, 1)

Solution steps

f^{'} (x) = - \frac{2 x}{( 1 + x ^{2} ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < \infty

Plug

x = 0

into

\frac{1}{1 + x ^{2}} : 1

Maximum (0, 1)

Popular Examples

monotone (4-x)/(x-1)monotone intervals

\frac{4 - x}{x - 1}

parity f(x)=xsqrt(8-x^2)parity

f (x) = x 8 - x^{2}

critical f(x)=((x+4))/(x^2)critical points

f (x) = \frac{( x + 4 )}{x ^{2}}

intercepts of f(x)=4x^3-12x^2-9x+27 intercepts

f (x) = 4 x^{3} - 12 x^{2} - 9 x + 27

inverse of f(x)= x/(7x-4)inverse

f (x) = \frac{x}{7 x - 4}

Frequently Asked Questions (FAQ)

What is the extreme f(x)= 1/(1+x^2) ?
The extreme f(x)= 1/(1+x^2) is Maximum(0,1)