What is the inverse of f(x)=\sqrt[3]{3x-2} ?

The inverse of f(x)=\sqrt[3]{3x-2} is (x^3+2)/3

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inverse of f(x)=\sqrt[3]{3x-2}

inverse

\frac{x ^{3} + 2}{3}

Solution steps

Replace

x

with

y

Solve for

\frac{x ^{3} + 2}{3}

y = x^{2} - 7 x

- 2 x^{2} + 25 x

\frac{2 ( - x ^{2} - 4 )}{( x ^{2} - 4 ) ^{2}}

f (x) = 3 x^{3} - 12 x^{2} - 15 x

f (x) = \frac{2 x ^{2} - x - 1}{x ^{2} + 4}

What is the inverse of f(x)=\sqrt[3]{3x-2} ?
The inverse of f(x)=\sqrt[3]{3x-2} is (x^3+2)/3