What is the perpendicular 7x-3y=-3 ?

The perpendicular 7x-3y=-3 is y=-3/7 x+b

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perpendicular 7x-3y=-3

perpendicular

7 x - 3 y = - 3

y = - \frac{3}{7} x + b

Solution steps

Find the slope of

7 x - 3 y = - 3 : m = \frac{7}{3}

Compute the slope of the perpendicular line:

m_{p} = - \frac{3}{7}

Line with slope m=

- \frac{3}{7} : y = - \frac{3}{7} x + b

y = - \frac{3}{7} x + b

ln (5 x)

x^{2} - \frac{1}{x}

2 x + 1

f (x) = \frac{x ^{2}}{2 x - 1}

(x^{2} - 3)^{3}