What is the extreme f(x)=4x^3-48x-8 ?

The extreme f(x)=4x^3-48x-8 is Maximum(-2,56),Minimum(2,-72)

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extreme f(x)=4x^3-48x-8

extreme points

f (x) = 4 x^{3} - 48 x - 8

Maximum (- 2, 56), Minimum (2, - 72)

Solution steps

f^{'} (x) = 12 x^{2} - 48

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

4 x^{3} - 48 x - 8 : 56

Maximum (- 2, 56)

Plug

x = 2

into

4 x^{3} - 48 x - 8 : - 72

Minimum (2, - 72)

Maximum (- 2, 56), Minimum (2, - 72)

f (x) = 7 x + 6 y = 6

f (x) = \frac{6 + 2 x}{4 - 7 x}

f (x) = \frac{x ^{2} + x - 2}{x ^{2}}

f (x) = \frac{2 - 7 x}{2 + 5 x}

f (x) = \frac{1}{( x - 2 ) ^{2}}

What is the extreme f(x)=4x^3-48x-8 ?
The extreme f(x)=4x^3-48x-8 is Maximum(-2,56),Minimum(2,-72)