What is the perpendicular x+3y=5,(2,5) ?

The perpendicular x+3y=5,(2,5) is y=3x-1

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perpendicular x+3y=5,(2,5)

perpendicular

x + 3 y = 5, (2, 5)

y = 3 x - 1

Solution steps

Find the line

y = mx + b

perpendicular to

x + 3 y = 5

that passes through

(2, 5)

Find the slope of

x + 3 y = 5 : m = - \frac{1}{3}

Compute the slope of the perpendicular line:

m_{p} = 3

Find the line with slope m=

3

and passing through

(2, 5) : y = 3 x - 1

y = 3 x - 1

1 + x + 2 x^{2} - x^{3}

f (x) = 2 - x + 9

\frac{2 x - 5}{x ( x - 3 )}

f (x) = sin (x + 3)

y = 3

What is the perpendicular x+3y=5,(2,5) ?
The perpendicular x+3y=5,(2,5) is y=3x-1