What is the perpendicular x+3y=-3 ?

The perpendicular x+3y=-3 is y=3x+b

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perpendicular x+3y=-3

perpendicular

x + 3 y = - 3

y = 3 x + b

Solution steps

Find the slope of

x + 3 y = - 3 : m = - \frac{1}{3}

Compute the slope of the perpendicular line:

m_{p} = 3

Line with slope m=

3 : y = 3 x + b

y = 3 x + b

5 x - 5 y = 7

y = x^{2} - 4 x + 6

f (x) = \frac{x}{5}

f (x) = - \frac{- 4 - 2 x}{9 + x}

f (x) = x^{\frac{1}{3}}