What is the domain of 1/(8(sqrt(2x+10))-16) ?

The domain of 1/(8(sqrt(2x+10))-16) is -5 -3

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domain of 1/(8(sqrt(2x+10))-16)

domain

\frac{1}{8 ( 2 x + 10 ) - 16}

- 5 \leq x < - 3 or x > - 3

Interval Notation

[- 5, - 3) \cup (- 3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 5

Find undefined (singularity) points:

x = - 3

Combine real regions and undefined points for final function domain

- 5 \leq x < - 3 or x > - 3

4 - 3 cos (4 x)

y = (x + 10)^{3}

- \frac{1}{2} x = 4 y

f (x) = - x - 16

f (x) = x^{2} - 5 x

What is the domain of 1/(8(sqrt(2x+10))-16) ?
The domain of 1/(8(sqrt(2x+10))-16) is -5<= x<-3\lor x>-3