What is the domain of f(x)=((sqrt(x)))/(3x^2+2x-1) ?

The domain of f(x)=((sqrt(x)))/(3x^2+2x-1) is 0 1/3

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domain of f(x)=((sqrt(x)))/(3x^2+2x-1)

domain

f (x) = \frac{( x )}{3 x ^{2} + 2 x - 1}

0 \leq x < \frac{1}{3} or x > \frac{1}{3}

Interval Notation

[0, \frac{1}{3}) \cup (\frac{1}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = \frac{1}{3}, x = - 1

Combine real regions and undefined points for final function domain

0 \leq x < \frac{1}{3} or x > \frac{1}{3}

y = x + 7

2 + x^{2} ln (x)

f (x) = \frac{6 x - 7}{11 x + 8}

g (x) = 1 - x

(2.1) (4.5)

What is the domain of f(x)=((sqrt(x)))/(3x^2+2x-1) ?
The domain of f(x)=((sqrt(x)))/(3x^2+2x-1) is 0<= x< 1/3 \lor x> 1/3