What is the critical f(x)=(x+3)(x-1)^2 ?

The critical f(x)=(x+3)(x-1)^2 is x=-5/3 ,x=1

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critical f(x)=(x+3)(x-1)^2

critical points

f (x) = (x + 3) (x - 1)^{2}

x = - \frac{5}{3}, x = 1

Solution steps

(x + 3) (x - 1)^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{5}{3}, x = 1

Identify critical points not in

f (x)

domain

Domain of

(x + 3) (x - 1)^{2} : - \infty < x < \infty

All critical points are in domain

x = - \frac{5}{3}, x = 1

(x - 2)^{2} + 3

x^{3} - 4 x^{2} + 4 x - 3

f (x) = \frac{2}{3} x - 4

3 x + 15 y = 45

x^{2} - 1

What is the critical f(x)=(x+3)(x-1)^2 ?
The critical f(x)=(x+3)(x-1)^2 is x=-5/3 ,x=1